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File:01. Директна синтеза на алуминиум бромид.webm

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Македонски: Експеримент во кој се демонстрира директна синтеза на алуминиум бромид од простите супстанци (елементите) алуминиум и бром. Реакцијата е многу бурна и може да се прикаже со равенката:
2Al(s) + 3Br2(l) = Al2Br6(Br2).

Продуктот е, како што назначува равенката, растворен во вишокот од бром.

Осмислено и изведено од Марина Стојановска, Миха Буклески и Владимир Петрушевски, Институт за хемија, ПМФ, УКИМ, Скопје.
English: Experiment showing direct synthesis of aluminum bromide from the elementary substances. The reaction is very vigorous and can be presented by the equation:
2Al(s) + 3Br2(l) = Al2Br6(Br2).

The product, as indicated by the equation, is dissolved in the excess bromine.

Planned and performed by Marina Stojanovska, Miha Bukleski and Vladimir Petruševski, Department of Chemistry, FNSM, Ss. Cyril and Methodius University, Skopje, Macedonia.
Français : Démonstration de synthèse de bromure d'aluminium.
La réaction s'écrit ainsi :
2Al(s) + 3Br2(l) = Al2Br6(Br2)
Expérience conçue, réalisée et expliquée par Marina Stojanovska, Miha Bukleski et Vladimir Petruševski de l'Institut de chimie de l'université Saints-Cyrille-et-Méthode de Skopje de Macédoine.
Български: Експеримент, в който се представя директен синтез на алуминиев бромид от алуминий и бром. Реакцията е много силна и може да се представи със следната формула:
2Al(s) + 3Br2(l) = Al2Br6(Br2).

Продуктът, както става известно от уравнението, се разтваря в излишъка от бром.

Експериментът е планиран и направен от Марина Стояновска и Владимир Петрушевски, Институт по химия, ПМФ, Скопски универистет "Св. св. Кирил и Методий", Република Македония.
中文：铝和溴的反应。反应十分剧烈，反应方程式如下：
2 Al(s) + 3 Br2(l) → Al2Br6(Br2)
产物溶解在过量的溴中。实验来自Marina Stojanovska, Miha Bukleski and Vladimir Petruševski, Department of Chemistry, FNSM, Ss. Cyril and Methodius University, Skopje, Macedonia。
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