Meta:Requests for oversight/MarcoAurelio
- The following discussion is preserved as an archive of a closed Meta-Wiki request. Please do not modify it.
- MarcoAurelio (talk • contribs • count • logs • page moves • block log • CA • email)
- Ending 22 December 2015 22:22 (UTC)
- This request is governed by the oversight policy. To be approved it requires at least 25 votes in favor and at least a level of support in pro-con voting no lower than 75%.
Hello. With the resignation of Billinghurst today, and the resignations of Pathoschild and the removal of Mardetanha for inactivity (both of them some time ago), it leaves Meta-Wiki with only three oversighters. I've been thinking for a while applying, because I myself regularly encounter material that fall under the oversight policy, mainly abusive usernames that we thought they were buried in the logs, but that with the SUL finalisation and the automatic welcome system reapears again, requiring removal because either contains personal information or otherwise they are degrading, offensive or plain attack usernames and I can't fully suppress those (nor the globalauth logs containing those names when the suppression log didn't existed; and "hidden" global accounts were publicy logged) with my current level of access, nor the userpages and user talk pages containing those usernames. Having this permission will help me in my routine work both as a regular here and as steward. I hope that you can support me for this sensitive role. Thank you. —MarcoAurelio 22:22, 15 December 2015 (UTC)
- Comments
- support —DerHexer (Talk) 22:28, 15 December 2015 (UTC)
- Support.—Teles «Talk to me ˱C L @ S˲» 22:38, 15 December 2015 (UTC)
- Support. Trusted, responsible, reliable - QuiteUnusual (talk) 22:52, 15 December 2015 (UTC)
- Support as ^ + clueful — billinghurst sDrewth 22:53, 15 December 2015 (UTC)
- Support - Clear case for me. However, I actually wanted to nominate you! -Barras talk 23:13, 15 December 2015 (UTC)
- Support --Kolega2357 (talk) 23:38, 15 December 2015 (UTC)
- Support Alan (talk) 00:01, 16 December 2015 (UTC)
- Support Jianhui67 talk★contribs 00:23, 16 December 2015 (UTC)
- Support Definitely. Trijnsteltalk 02:28, 16 December 2015 (UTC)
- Support QuiteUnusual has pointed it all :( ~ Nahid Talk 06:31, 16 December 2015 (UTC)
- Support Yeah. eurodyne (talk) 06:58, 16 December 2015 (UTC)
- Support Off-course! No better candidate. Syum90 (talk) 07:41, 16 December 2015 (UTC)
- Support --Stryn (talk) 07:51, 16 December 2015 (UTC)
- Strong support Yup. Theo10011 (talk) 08:18, 16 December 2015 (UTC)
- Support One of the best admins we have at Meta and per others above. --Glaisher (talk) 08:40, 16 December 2015 (UTC)
- Support ~ Moheen (talk) 11:29, 16 December 2015 (UTC)
- Strong support Clear case.--Infinite0694 (Talk) 13:10, 16 December 2015 (UTC)
- Support. –Ejs-80 13:32, 16 December 2015 (UTC)
- Support .--Grind24 (talk) 15:08, 16 December 2015 (UTC)
- Support happily --Herby talk thyme 16:47, 16 December 2015 (UTC)
- Support --Defender (talk) 17:30, 16 December 2015 (UTC)
- Support --Krd 18:33, 16 December 2015 (UTC)
- Support --Shanmugamp7 (talk) 05:41, 17 December 2015 (UTC)
- Support - Taketa (talk) 12:15, 17 December 2015 (UTC)
- Support - definitely. --Pmlineditor (t · c · l) 17:03, 17 December 2015 (UTC)
- Support--6AND5 (talk) 21:02, 17 December 2015 (UTC)
- Support--Lanwi1(Talk) 23:14, 17 December 2015 (UTC)
- Support -FASTILY 09:37, 19 December 2015 (UTC)
- Support --Rschen7754 18:28, 19 December 2015 (UTC)
- Support Matanya (talk) 22:41, 19 December 2015 (UTC)
- Support -- Wagino 20100516 (talk) 23:27, 19 December 2015 (UTC)
- Support --Wiki13 talk 23:30, 19 December 2015 (UTC)
- Support --Az1568 (talk) 00:26, 20 December 2015 (UTC)
- Support Ruy Pugliesi◥ 04:38, 20 December 2015 (UTC)
- Support. Érico (msg) 19:24, 22 December 2015 (UTC)
- Rather clear result. Successful. -Barras talk 22:23, 22 December 2015 (UTC)
- The above request page is preserved as an archive. Please do not modify it. Comments about this page should be made in Meta:Babel or Meta:Requests for help from a sysop or bureaucrat.